TennisATPRight-handed
Petar Jelenic
CroatiaAge, ranking and resultsPetar Jelenic competes on the ATP Tour, represents Croatia, and reached a career-high ATP Tour ranking of No. 467 on February 8, 2010.
Updated
About Petar Jelenic
Petar Jelenic, who represents Croatia and competes on the ATP Tour, was born on June 13, 1987, in Split, SR Croatia, SFR Yugoslavia. He plays right-handed with a two-handed backhand. On February 8, 2010, he reached a career-high ATP Tour ranking of No. 467.
Agatha Research DeskUpdated Oct 5, 2026Match history2
Every ATP Tour, Grand Slam and Olympic main-draw match in our records, newest first. A walkover is listed but never counted in a record.
| Date | Tournament | Round | Opponent | Result | Score | Surface |
|---|---|---|---|---|---|---|
| Feb 4 | ATP PBZ Zagreb Indoors | Round 2 | Michael Berrer | L | 4-6, 3-6 | Hard |
| Feb 2 | ATP PBZ Zagreb Indoors | Round 1 | Ilija Bozoljac | W | 7-6(6), 7-5 | Hard |
How he is doing now
Career
- 2010First ATP matchBeat Ilija Bozoljac, ATP PBZ Zagreb Indoors
- 2010Career high No. 467Feb 8, 2010
- Feb 4, 2010Latest matchLost to Michael Berrer, ATP PBZ Zagreb Indoors
First ATP match
Feb 2, 2010: beat Ilija Bozoljac 7-6, 7-5ATP PBZ Zagreb Indoors, on hard
Latest match
Feb 4, 2010: lost to Michael Berrer 4-6, 3-6ATP PBZ Zagreb Indoors, Round 2, on hard court
Sources and updates
Results and schedules come from Agatha's own records of the ATP Tour.
Updated Oct 5, 2026, 3:12 PM ET. Results and form refresh after every match; biography facts are checked weekly.